I'm building my packs with 0.15mm thick pure nickel strips that have no pattern (one piece of about 27mm wide nickel) so instead of having the typical 8mm wide serial connection, I have an area that is as wide as the cell (18mm).
So 18*0.15=2.7 which I devide that 2.7 by 4 in order to get the square area of the conductor in copper language which is 0.67mm that is about 19AWG copper wire per cell.
The strongest cell I use is 25R which I draw a max of 10A (half of the rated discharge rate).
So 10A through 19AWG.
I calculated that the length of the conductor between each two cells is about 10mm and if I multiply it for a 20S pack then I have 19 pieces of 10mm which is 19cm of total 19AWG length.
Can it be calculated like this?
If so, how do I calculate the resistance and voltage drop of 10A across a 19cm long 19AWG (0.65mm2) copper wire?
So 18*0.15=2.7 which I devide that 2.7 by 4 in order to get the square area of the conductor in copper language which is 0.67mm that is about 19AWG copper wire per cell.
The strongest cell I use is 25R which I draw a max of 10A (half of the rated discharge rate).
So 10A through 19AWG.
I calculated that the length of the conductor between each two cells is about 10mm and if I multiply it for a 20S pack then I have 19 pieces of 10mm which is 19cm of total 19AWG length.
Can it be calculated like this?
If so, how do I calculate the resistance and voltage drop of 10A across a 19cm long 19AWG (0.65mm2) copper wire?