Hey guys i'm soon to attempt to wire up my first BMS for a 15s LiPo battery pack based on 3 of these: https://www.hobbyking.com/hobbyking/store/uh_viewItem.asp?idProduct=22586
So far i have opened one of these packs and separated the cells into 2 groups of 5s as to wire up each half in series with one of the other packs to create 2X 15s packs ( each pack is made up of 2 5s packs wired in series with separate balancing cables for each group of 5 so easy done ) these remade packs will be wired in parallel to provide 15s at 9Ah
I have measured each cell voltage:
*Total v refers to the voltage difference between the Negative wire coming from the battery pack and the most positive wire on the balance lead (red).
There is one cell at 3.51V which is a concern at this point. note that cells (1,2) (5,6) are the premade packs, and (3,4) has been separated into 2X5s
I now plan on wiring these cells like this:
Packs 1 and 2 will be wired in parallel and balance leads combined to wire into the BMS.
Am i on the right track? my concern is that when combining the cell at 3.51v with the one at 3.82v it will damage the cell.
So far i have opened one of these packs and separated the cells into 2 groups of 5s as to wire up each half in series with one of the other packs to create 2X 15s packs ( each pack is made up of 2 5s packs wired in series with separate balancing cables for each group of 5 so easy done ) these remade packs will be wired in parallel to provide 15s at 9Ah
I have measured each cell voltage:
*Total v refers to the voltage difference between the Negative wire coming from the battery pack and the most positive wire on the balance lead (red).
There is one cell at 3.51V which is a concern at this point. note that cells (1,2) (5,6) are the premade packs, and (3,4) has been separated into 2X5s
I now plan on wiring these cells like this:
Packs 1 and 2 will be wired in parallel and balance leads combined to wire into the BMS.
Am i on the right track? my concern is that when combining the cell at 3.51v with the one at 3.82v it will damage the cell.