Samson
1 W
Over the last several weeks I have built my first Ebike. It is a low power set up using a 250 Watt geared Hub motor and 14S 10 Ahr Headways with a Cell man BMS. I keep the bike in the garage but I have the charger inside the house so I can monitor the charging cycle easily. To do this I ran a 2 conductor #14 AWG cable from a wall box termination at the charger to the bike XLR connector. The length is 35 feet total run. I calculated the voltage drop over this run based on the wire resistance of 35 feet x 2 conductors = 70 feet and the bikes Schottky protection diode (reverse polarity protection) forward voltage drop to be as follows with various current draw:
Charge current to produce 3.65 volts per cell taking the bike diode drop and wire resistance into account:
Charge: 10 Amps 14 cells x 3.65 V +.50 V diode drop + 2.29 V wire drop at 10 amps = 53.9 VDC
Charge: 7 Amps 14 cells x 3.65 V +.47 V diode drop + 1.60 V wire drop at 7 amps = 53.2 VDC
Charge: 5 Amps 14 cells x 3.65 V +.45 V diode drop + 1.14 V wire drop at 5 amps = 52.7 VDC
Charge: 1 Amps 14 cells x 3.65 V +.40 V diode drop + .229 V wire drop at 1 amps = 51.7 VDC
Charge: 100 mA 14 cells x 3.65 V +.34 V diode drop + .0229 V wire drop at 100 mA = 51.1 VDC
edit: corrected 100 mA Calculation
The BMS temperature is monitored back in the house with a digital thermometer probe on the BMS balance resistors so I can infer what the BMS is doing.
From the above table at 5 Amps charge I need to terminate at 52.7 volts and then drop to 51.1 V for the rest of the charge cycle to allow the BMS to balance the pack for 1-2 hours or so. If I leave the charger at 52.7 V after the current drops off the BMS gets very hot (75 deg C) and cycles on and off with HVC. Dropping the charge voltage to 51.1 Volts prevents this and the BMS runs at about 12 deg C over ambient.
Does this charge strategy make sense or do you let the BMS run hot?
Charge current to produce 3.65 volts per cell taking the bike diode drop and wire resistance into account:
Charge: 10 Amps 14 cells x 3.65 V +.50 V diode drop + 2.29 V wire drop at 10 amps = 53.9 VDC
Charge: 7 Amps 14 cells x 3.65 V +.47 V diode drop + 1.60 V wire drop at 7 amps = 53.2 VDC
Charge: 5 Amps 14 cells x 3.65 V +.45 V diode drop + 1.14 V wire drop at 5 amps = 52.7 VDC
Charge: 1 Amps 14 cells x 3.65 V +.40 V diode drop + .229 V wire drop at 1 amps = 51.7 VDC
Charge: 100 mA 14 cells x 3.65 V +.34 V diode drop + .0229 V wire drop at 100 mA = 51.1 VDC
edit: corrected 100 mA Calculation
The BMS temperature is monitored back in the house with a digital thermometer probe on the BMS balance resistors so I can infer what the BMS is doing.
From the above table at 5 Amps charge I need to terminate at 52.7 volts and then drop to 51.1 V for the rest of the charge cycle to allow the BMS to balance the pack for 1-2 hours or so. If I leave the charger at 52.7 V after the current drops off the BMS gets very hot (75 deg C) and cycles on and off with HVC. Dropping the charge voltage to 51.1 Volts prevents this and the BMS runs at about 12 deg C over ambient.
Does this charge strategy make sense or do you let the BMS run hot?