The following is more for someone building their FIRST ebike 18650 battery
using salvaged cells that may be too "dissimilar" in capacity and internal resistance. ALL the cells first need to be thoroughly tested so as to eliminate cells of less capacity or higher internal resistance (outliers/duds). At least 10% of the salvaged cells may be outliers because of lessor capacity, higher IR or higher than normal self-discharge (more of a problem with high energy dense salvaged cells). That said would appreciate any feedback from
docw009 and others that a knowledgeable first-time DIY builder can grasp ... "dissimilar" versus what qualifies as "similar" for a general purpose 10s5p DIY ebike battery build using salvaged cells ?
This thread about "dissimilar" cells (DIY build) is worth discussing further. For example at what point are
salvaged cells considered "similar" enuf (not "dissimilar") in both capacity and IR for fabricating a worthwhile DIY ebike 18650 battery build ? We can agree that the example by
docw009 is definitely with "dissimilar" cells and definitely a No-No.
Whether to use "dissimilar" Li-ion 18650 salvaged cells for your 1st DIY build is always a gamble with the odds against the DIY builder. First-off most all agree that paralleling "dissimilar" salvaged cells, especially no name brand cells, is a NO-NO. By definition "dissimilar" means it's too much of a gamble that in the end wasn't worth the effort even if the cells were FREE.
HOWEVER, as long as the salvaged cells have same chemistry (e.g. NMC), similar capacity and internal resistance (w/data sheet) it's worth the effort (depending on your application). If the cells (unused, but outdated) aren't a familiar brand with no datasheet don't waste your money no matter how cheap the lot of cells.
You need the right equipment to thoroughly test all of the "similar" salvaged cells so as to eliminate the outliers/duds. Doing so will then make it possible to arrange the cells so each parallel group is as similar as possible in both capacity and internal resistance. The higher the current demand (using high energy dense cells) the more important it is for each parallel group to have similar capacity and similar low internal resistance.
docw009 said:
Sure. I ran the pack on my ebike and based on my past knowledge of its consumption, using wattmeters, etc, my mileage when the battery shut off corresponded to 6AH. Every cell in that battery had been measured for both capacity and IR. All the 22P's over 2000 mah. The two MH1's at 3100 mah, The simple model gives 10ah for banks 1-9, and 12.2AH for the last bank. Got a real life value of 6AH,
Summary, IMO: The BMS LVC set at 3.0V was triggered by the #10 5p bank (2-MH1, 3-22P), while the other nine parallel banks were at 50% SOC. The one factor never mentioned was your average amperage drain as that 10s5p battery neared and reached the BMS LVC of 3.0V (#10 5p bank). If the average ending amperage drain was at a 7Ah drain rate versus say a 14Ah drain rate then wouldn't the "real life value" have been noticeably higher (e.g. 8.0Ah vs 6.0Ah guesstimate). In other words you wouldn't have hit #10p 3.0V BMS LVC as soon if the bldc motor was only pulling a 7Ah rate instead of a 14Ah rate.
docw009 said:
So I exaggerated when I said the LG's did all the work, That last bank of cells somehow managed to burn 5AH and not send it to my motor. I'll take the explanation above that the strong cells went low, and the weaker ones recharged them.
Summary, IMO: Indirectly the #10 5p bank of cells (2-MH1, 3-22P) was actually supplying current to the bldc motor. The reason the two MH1 cells drained faster was due to its lower IR and greater current demand (e.g. 14amp drain) by the bldc motor (probably a 20amp Controller). Thus #10 5p bank first reaching the BMS LVC of 3.0V; while banks #1-#9 5p where still higher (50% SOC=3.65V). Even if the LVC of the Controller was set at 32.0V (3.2V x 10p = 32.0V) the battery was still at 35.85V (3.65V x 1p-9p = 32.85V + 3.0V (#10p) = 35.85V.
One factor that i don't believe has ever been discussed in this ES forum is the difference in resistance between 22P cell and MH1 cell when under a load (e.g. 14Ah) compared to when at rest. Is it possible that the IR difference between MH1 cells and 22P cells is even more noticeable when suppling a high demand for currrent (at rest vs 14Ah drain). For example when tested individually at rest the IR difference between the two is only a difference of 10 milliohms (40mO vs 30mO). However, when drained at a high rate (14Ah) the difference in IR may be at least 30mO instead of just 10mO (IR at rest).
Questions:
1. What was the bldc motors' current demand on your battery leading to only 3.0V on #10 5p bank triggering the BMS LVC ?
2. Is there more than a 10mO difference in IR of a 18650 Li-ion 5p bank when tested at rest compared to when tested being drained at 14Ah? Thus the IR of 5p 22P vs 5p 2-MH1, 3-22P is more signifigant under a load then at rest ?
3. What is the IR of a 5p 22P bank at rest (_______) vs a 5p 2-MH1, 3-22P bank at rest (_______) ?
4. Do you know if the IR difference of a 5p 22P bank vs a 5p (2-MH1, 3-22P) bank under a 14Ah drain rate is more than the same 5p IR difference at rest? My guess is YES ... thus why the #10 5p bank with lower IR (e.g. 14Ah rate) was drained even faster. When #10 5p bank hit, 3.0V triggering the BMS LVC the two MH1 cells may have been as low as 2.5V, and the three 22P cells at 3.45V (5V + 10.2V - 15.2 / 5 = 3.04V). However, after a 2 hr rest with bounce back voltage the MH1 cells were closer to say 3.0V and the 22P cells closer to say 3.60V (just a guesstimate).
The greater the current drain (14Ah vs 7Ah) the sooner the BMS LVC of 3.0V is triggered. Likewise, the greater is the bounce back voltage at 14Ah drain rate than 7Ah drain rate.