1) is very simple. Just draw two lines labeled 0 and Vbus. Now rotate the 3 phase star inside those two lines... What's the maximum length of the Star arms (phase voltages) that can rotate in that space? Simple triangle trigonometry. This should be self evident... The inverter cannot output voltages outside 0 to Vbus.Ok thank you very much for the reply, i am really confused with 2 other questions, i don't get answers
1. When we apply FOC what is the maximum bus voltage applied on the phases (line voltage or phase voltage), if the applied voltage from the power supply is Vbus. I read it is 2/sqrt(3)*Vbus. Is there a simple derivation?
2. Similarly if the input DC current is Idc what is the phase current applied. I mean what is the relation if the torque applied is T?
Thank you in advance.
This is what i tried but got stuck up. Could you please help me with next steps?1) is very simple. Just draw two lines labeled 0 and Vbus. Now rotate the 3 phase star inside those two lines... What's the maximum length of the Star arms (phase voltages) that can rotate in that space? Simple triangle trigonometry. This should be self evident... The inverter cannot output voltages outside 0 to Vbus.
You don't need the circle. You have to imagine rotating it without the circle. The middle would go up and down if the vectors were bigger but that's not a problem.This is what i tried but got stuck up. Could you please help me with next steps?
View attachment 341288
Think harder.View attachment 341296
I think it is VBus/2 the maximum vector of U.